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SAT Math Sample Questions

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The quadratic function f is graphed in the xy-plane, where y = f(x). One of the x-intercepts of this graph is ( 15 / 4 , 0) and its vertex is (2, 5). What is the other x-intercept?

A. (- 15 / 4 , 0)
B. (- 7 / 4 , 0)
C. ( 1 / 4 , 0)
D. ( 23 / 4 , 0)
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Hint: The graph of a quadratic function is a parabola. A parabola has a vertical axis of symmetry that passes through its vertex.

The graph of a quadratic function is a parabola. The parabola’s vertex is on a vertical axis of symmetry that is halfway between any two points on the parabola that have the same y-value.

All x-intercepts have the same y-value, so the vertex is halfway between the x-intercepts. Therefore, the x-value of the vertex is equal to the average of the x-intercepts.

Find the horizontal distance between the axis of symmetry and the given x-intercept. Then use this distance to find the x-intercept that is on the other side of the axis of symmetry.

Note: It may be simpler to consider the values in decimal form.

The given x-intercept is 1.75 units to the right of the axis of symmetry (x = 2), so the other x-intercept must be 1.75 units to the left of it. Subtract to see that the other x-intercept is 2 − 1.75 = 0.25.

Rewrite 0.25 as 1 / 4 to match the form of the choices. Therefore, the other x-intercept of the graph of f(x) is ( 1 / 4 , 0)

Note: It is also possible to set up an equation for the average of the x-intercepts and solve for the other x-intercept.

(Choice A) (- 15 / 4 , 0) may result from mistaking the axis of symmetry to be the y-axis (instead of the line x = 2).

(Choice B) (- 7 / 4 , 0) may result from calculating the horizontal distance between the given x-intercept and the vertex and then subtracting it from 0 (instead of from 2).

(Choice D) ( 23 / 4 , 0) may result from adding the x-values of the vertex and the given x-intercept. It is possible to eliminate this choice because it is on the same side of the vertex as the given x-intercept.

Things to remember:
A parabola has a vertical axis of symmetry that passes through its vertex. The axis of symmetry is halfway between any two points on the parabola that have the same y-value.

A rectangle has a length of 8 inches and a width of 11 inches. What is the perimeter, in inches, of this rectangle?

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Hint : The perimeter of a polygon is equal to the sum of the side lengths.

The perimeter of a polygon is equal to the sum of the side lengths. Both pairs of opposite sides of a rectangle are congruent, so the formula for the perimeter of a rectangle with length l and width w is P = 2l + 2w .

Perimeter of a rectangle

P = 2l + 2w

It is given that the length is 8 inches and the width is 11 inches. Plug in l = 8 and w = 11 and solve for P.

The perimeter of this rectangle is 38 inches.

Things to remember:

  • The perimeter of a polygon is equal to the sum of its side lengths.
  • Both pairs of opposite sides of a rectangle are congruent, so the perimeter of a rectangle with length l and width w is P = 2l + 2w .

On a certain date, the average price per barrel of crude oil was $31.68. The average price increased at a constant rate every day for x days, until the price per barrel reached $31.92. The equation 31.68 + 0.048x = 31.92 represents this situation. Which of the following best describes the meaning of the number 0.048 in the equation?

  1. The total increase, in dollars, in the average price per barrel of crude oil after x days
  2. The average price per barrel of crude oil
  3. The percentage increase in the average price per barrel of crude oil
  4. The rate of change, in dollars per day, in the average price per barrel of crude oil
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Hint : In the given equation, the values 31.68 and 31.92 represent dollar amounts, so 0.048x must also represent a dollar amount.

The given equation 31.68 + 0.048x = 31.92 models the average price per barrel of crude oil where the price increased from $31.68 to $31.92.

Therefore, 0.048x is the increase in the average price per barrel after x days. Each term in an equation must have the same units, so the units of 0.048x must be dollars.

It is given that the price increased at a constant rate every day, so an increase of 0.048x dollars means that the price increased 0.048 dollars per day for x days.

Therefore, 0.048 is the rate of change, in dollars per day, in the average price per barrel of crude oil.

(Choice A) This choice describes the meaning of 0.048x (instead of 0.048).

(Choice B) This choice is incorrect because the average price per barrel starts at $31.68 and increases each day for x days to $31.92.

(Choice C) This choice may result from mistaking x to be the average price per barrel (instead of a number of days).

Things to remember:
A total amount (ex. cost, time) is generally a fixed amount (ex. initial amount) plus any variable amount (ex. number of items multiplied by the rate per item).

Which of the following is an equivalent form of k2 − 14km + 49m2 ?

  1. (k + 7m)2
  2. (k – 7m)2
  3. (k + 2m)(k − 7m)
  4. (k + 7m)(k − 7m)
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Hint : The first and third terms in the given expression are perfect squares.

An expression in the form a2 − 2ab + b2 factors as the perfect square (ab)2 (proof).

In the given expression k 2 − 14km + 49m2, the term k 2 is equivalent to kk and the term 49m 2 is equivalent to 7m ∙ 7m. These terms are perfect squares k 2 and (7m)2.

The remaining term 14km is equivalent to 2 ⋅ k ⋅ 7m, so the given expression factors as a perfect square.

The given expression is equivalent to (k − 7m)2.

(Choice A) (k + 7m)2 is equivalent to k 2 + 14km + 49m2 and may result from mistakenly factoring the given expression as (a + b)2, instead of (ab)2.

(Choice C) (k + 2m)(k − 7m) is equivalent to k 2 − 5km − 14m2 (instead of k 2 − 14km + 49m2).

(Choice D) (k + 7m)(k − 7m) is equivalent to k 2 − 49m2 and may result from mistakenly factoring the given expression as a difference of two squares a2b2.

Things to remember:

  • An expression in the form a2 + 2ab + b2 factors as the perfect square (a + b)2.
  • An expression in the form a2 − 2ab + b2 factors as the perfect square (ab)2.

Alternate Method :

It is also possible to expand each choice and simplify to see which is equivalent to k 2 − 14km + 49m2.

Each choice is equivalent to a product of two binomials. Distribute each term in the first factor to each term in the second, and then combine like terms.

The expression that is equivalent to the given expression is (k − 7m)2.

In the figure above, points A, B, and C lie on the circle. What is the measure, in degrees, of arc AC ?

  1. 15
  2. 30
  3. 60
  4. 330
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Hint : The measure of an arc is equal to the measure of its intercepting central angle.

The measure of an arc is equal to the measure of its intercepting central angle. The central angle theorem states that the measure of a central angle is twice that of any inscribed angle that intercepts the same arc.

Therefore, the measure of an arc is twice that of its intercepting inscribed angle. No central angle is given, so use the measure of inscribed ∠ABC (30°). Multiply 30° by 2 to find the measure of intercepted arc AC

The measure of arc AC is 60°.

Note: The measure of an arc is an angle measurement. It is distinct from arc length, which is a part of the circumference of a circle.

(Choice A) 15 may result from mistaking the measure of an arc to be half (instead of twice) the measure of the intercepting inscribed angle.

(Choice B) 30 may result from mistaking the measure of an arc to be the same as (instead of twice) the measure of the intercepting inscribed angle.

(Choice D) 330 may result from a combination of the error described in Choice B and subtracting the incorrect measure from 360°.

Things to remember:

  • The measure of an arc is equal to the measure of its intercepting central angle.
  • The central angle theorem states that the measure of a central angle is twice the measure of any inscribed angle that intercepts the same arc.

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Features: My Notebook & Flashcards

  • Transferring QBank visual and written content to your digital My Notebook and Flashcards is a breeze. Effortlessly create notes or flashcards by simply clicking, highlighting, and selecting information you’d like to review later.
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Frequently Asked Questions (FAQs)

Yes, the UWorld SAT Math practice tests replicate the actual structure of the SAT.
You can generate as many customized practice tests as you can handle. Create a new test based on a topic, custom tag, or just questions you’ve previously answered incorrectly.
Our SAT Math tests and practice questions have been developed by an in-house team of subject-matter experts to meet or exceed exam level difficulty.
UWorld’s SAT Math practice tests are only available in online, or digital, format.
Yes, our advanced performance tracking tools monitor your progress by providing score predictors, identifying your weaknesses in real time, comparing your results to your peers, and giving you feedback summaries for each test.
Our practice questions and tests are routinely updated by our in-house team of subject matter experts to reflect the current SAT Math format and difficulty.
We offer video tutorials, but we do not offer personalized tutoring options.
Our practice tests are customizable. Any student who is ready to start preparing for the SAT Math is ready to start studying with our practice tests.
Yes, all UWorld SAT Math products are available on your desktop computer, laptop, tablet, and smartphone. All of your data is saved and synced across devices, so you won’t lose your progress.
The best results come from consistently engaging in short study sessions—ideally, at least 20 minutes and no longer than an hour—along with consistent practice spanning several months. To unlock your maximum potential, we advise beginning your SAT Math test preparation at least six months to a year before your scheduled exam date. However, it is common for students to start their test prep between one and three months prior to the actual exam. Although practicing consistently over an extended period is ideal, even dedicating just one month to focused study can yield significant improvements.
Dedicate as much time as you need to learn how to approach each type of question. Use the performance dashboard’s real-time reports to identify in which subjects and question types you have made errors. These areas present the greatest potential for score improvement, allowing you to effectively focus your efforts. As you gain mastery of how to approach each question type, incorporate time limits to replicate the authentic experience of the SAT Math test.
When approaching difficult SAT Math problems, consider working backwards from the answer choices, eliminating answer choices, breaking down complex problems into manageable steps, or drawing diagrams to help visualize a problem.

Setting the goal of getting a high score on the SAT Math section may make you anxious. It’s too big, too general, and too difficult to measure

Let’s explore how to make this goal manageable:

  • Take a self-assessment with score prediction to set a baseline and determine which topics are a challenge to you.
  • Create your overarching goal. (e.g. “Improve my Math score by 100 points in 3 months.”)
  • Break down your smaller goals. (e.g., “Practice a mix of 20 geometry and calculus problems per day, review for mistakes, and create a flashcard identifying the blind spot responsible for that mistake.)
The College Board® SAT Math tests four “types” of math—heart of algebra, problem solving and data analysis, passport to advanced math, and additional topics on math. UWorld’s SAT Math practice tests cover all topics. Learn more about these topics on our “About the SAT Math page”.
UWorld’s advanced performance analytics provide real-time feedback, so you can track your progress and identify your weaknesses. Next, hone in on those weaknesses with targeted study. Then take a customized practice exam and see how you’ve improved.
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