ACT® Math Practice Tests and Questions
Free Sample ACT Math Questions
Question
The Summer Olympic Games are among the most-watched internationally televised sporting events and have been held in over 20 different countries. The table below gives the number of U.S. viewers, in millions, for 8 Summer Olympics opening ceremonies located in different international cities.
What is the median number of viewers, in millions, of these 8 Summer Olympics opening ceremonies?
| A. 26.6 | |
| B. 27.8 | |
| C. 28.6 | |
| D. 30.2 |
Hint :
The median is the middle of a numerically ordered data set. When the number of values is odd, the median is the middle value. When it is even, the median is the average of the two middle values.
Explanation
The median of a data set with an even number of values is the average of the middle two values when all values are ordered numerically.
The given data set has 8 values, but the values are not in order. First order the number of U.S. viewers from least to greatest.
There are 8 values in the given table, so the median is the average of the 4th and 5th ordered numbers.
The median number of U.S. viewers of these 8 Summer Olympics opening ceremonies is 28.6 million.
(Choice A) 26.6 is the average of the middle two values of the unordered list of numbers of viewers. However, the median is the average of the middle two values when all values are ordered numerically.
(Choice B) 27.8 is the smallest of the middle two values of the ordered list of numbers of viewers. However, the median of a data set with an even number of values is the average of the middle two values.
(Choice D) 30.2 is the mean of the number of viewers. However, the question asks for the median of the number of viewers.
Things to remember:
The median is the middle value of a data set that is ordered numerically. When the number of values is odd, the median is the middle value. When it is even, the median is the average of the two middle values.
Question
A box contains 12 flavored candies: 5 lime, 4 cherry, 1 orange, and 2 grape. Which of the following expressions gives the probability of choosing, at random and without replacement, a cherry candy for the first choice, a lime candy for the second choice, and a cherry candy for the third choice?
| A.
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| B.
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| C.
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| D.
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Hint :
The probability that dependent events occur is equal to the probability that the first event occurs multiplied by the probability that each consecutive event occurs, given that each preceding event has already occurred.
Explanation
The candies are chosen without replacement (they are not replaced in the box after being chosen), so each event of choosing a candy affects the probability of the events that follow. Therefore, the events are dependent.
The probability that dependent events occur is equal to the probability that the first event occurs multiplied by the probability that each consecutive event occurs, given that each preceding event has already occurred.
The 1st event is that a cherry candy is chosen and not replaced in the box. The 2nd event is that a lime candy is chosen and not replaced, and the 3rd event is that a cherry candy is chosen and not replaced.
Therefore, the probability that a cherry candy is chosen first, a lime candy is chosen second, and a cherry candy is chosen third is:
Use the following formula to find the probability P of each event:
P(cherry 1st)
The first event is that a cherry candy is chosen first from the box.
The number of desired outcomes for choosing cherry is the number of cherry candies in the box.
The total number of possible outcomes for choosing cherry is the total number of candies in the box.
It is given that there are 4 cherry candies in the box, and it is given that the box contains a total of 12 candies. Therefore, the probability of choosing a cherry first is .
P(lime 2nd)
The probability that a lime candy is chosen second depends on the first event that a cherry candy is chosen, so it is the probability given that the first chosen candy is cherry.
The number of desired outcomes is the number of lime candies after a cherry candy is removed.
The number of possible outcomes is the number of candies remaining after a cherry candy is removed.
It is given that the full box had 5 lime candies. After a cherry candy is removed, there are still 5 lime candies and a total of 12 − 1 = 11 candies remaining.
Therefore, the probability of choosing a lime candy second is .
P(cherry 3rd)
The probability that a cherry candy is chosen third depends on the first event and the second event, so it is the probability given that the first chosen candy is cherry and the second chosen is lime.
The number of desired outcomes is the number of cherry candies remaining. The total number of possible outcomes is the number of candies remaining after a cherry and lime candy are removed.
It is given that the full box had 4 cherry candies. A cherry candy and then a lime candy were removed, so there are 4 − 1 = 3 cherry candies remaining and a total of 12 − 2 = 10 candies remaining.
Therefore, the probability of choosing a cherry candy third is .
P(cherry 1st, lime 2nd, and cherry 3rd)
Now multiply the individual probabilities to find the probability that all three events occur.
| Probability of cherry 1st, lime 2nd, and cherry 3rd | |
| Plug in probabilities |
The probability of choosing, at random and without replacement, a cherry candy first, a lime candy second, and a cherry candy third is .
(Choice A) may result from mistaking the total number of candies in the box to be 12 with each choice. However, the total number of candies in the box decreases by 1 each time a choice is made without replacement.
(Choice B) is the probability of choosing a cherry candy, a lime candy, and a cherry candy with replacement instead of without replacement.
(Choice C) may result from mistaking the number of cherry candies in the box for the third choice to be 4. However, the number of cherry candies in the box decreases by 1 each time a cherry candy is chosen without replacement.
Things to remember:
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To find the probability of a single event, use the following formula:
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Two events are dependent if one event affects the other.
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To find the probability that two dependent events occur, multiply their individual probabilities together.
Question
For all real values of x, which of the following is the solution set of 3x + 9 ≥ −12 ?
| A. x ≤ −1 | |
| B. x ≥ −1 | |
| C. x ≤ −7 | |
| D. x ≥ −7 |
Hint :
To find the solution set of an inequality in one variable, isolate the variable by itself on one side of the inequality.
Explanation
The solution set of an inequality with one variable is the set of all values of the variable that make the inequality true. To find the solution set, solve for the variable in the inequality.
To solve for x in the given inequality 3x + 9 ≥ −12, subtract 9 from both sides and divide by 3 to isolate x so it is by itself on one side of the inequality.
| 3x + 9 ≥ −12 | |
| 3x ≥ −21 | Subtract 9 from both sides |
| x ≥ −7 | Divide both sides by 3 Note: The inequality sign remains unchanged because 3 is positive. |
Therefore, the solution set of the given inequality is x ≥ −7.
(Choice A) x ≤ −1 may result from a combination of the errors described in Choices B and C.
(Choice B) x ≥ −1 may result from incorrectly subtracting −12 − 9 to get −3 (instead of −21).
(Choice C) x ≤ −7 may result from mistakenly reversing the direction of the inequality. The inequality sign only reverses as a result of multiplying or dividing both sides by a negative number.
Things to remember:
- To find the solution set of an inequality in one variable, isolate the variable by itself on one side of the inequality.
- The solution set of an inequality is the set of all values that make the inequality true.
Question
Bart's Burgers sells different sizes of drinks. The number of ounces and the sale price per drink for each of the 3 sizes are given in the table below. The sale price is the amount a customer pays for that drink.
The average sale price per ounce of a large (L) drink is closest to which of the following amounts?
| A. $0.07 | |
| B. $0.15 | |
| C. $0.20 | |
| D. $0.67 |
Hint :
Use the given table to identify the sale price and the number of ounces per large (L) drink.
Explanation
The average price per item is equal to the price of the items divided by the number of items.
The question asks for the average sale price per ounce of a large (L) drink.
The total price of the items is the price per L drink.
The total number of items is the ounces per L drink.
Identify from the given table that the price of an L drink is $1.60 and the number of ounces in an L drink is 24.
Plug these values into the formula above and divide to find the average sale price per ounce.
| Average sale price per ounce | |
| Plug in price and number of ounces | |
| Divide | |
| Round to match answer choices |
The average sale price per ounce of a large (L) drink is $0.07.
(Choice B) $0.15 may result from mistakenly dividing the number of ounces in a large drink by an incorrect price, but the average sale price per ounce is price divided by ounces.
(Choice C) $0.20 may result from mistakenly dividing the price of a large drink by the number of ounces in a small drink (instead of in a large drink).
(Choice D) $0.67 may result from a calculation error when dividing $1.60 by 24 to get $0.66… (instead of $0.066…).
Things to remember:
The average price per item is equal to the price of the items divided by the number of items.
Question
An electronics company has an incentive program in which account representatives can earn money based on their monthly sales. Representatives can earn bonus pay based on their single highest sale for the month.
In a certain month, account representatives at the electronics company earned bonus pay that totaled $9,500. What is the maximum number of representatives whose single highest sale that month could have been in the range of $20,000–$39,999?
| A. 4 | |
| B. 5 | |
| C. 9 | |
| D. 10 |
Hint :
The maximum number of representatives whose single highest sale could have been in the given range is equal to the greatest whole number of bonuses for that range that could have been paid with the given total bonus.
Explanation
The number of representatives is equivalent to the number of bonuses paid, so find the maximum number of bonuses that could have been paid with the given total.
Divide the given total bonus pay by the bonus for a single highest sale in the range of $20,000–$39,999 to determine the maximum number of bonuses.
The given total bonus pay was $9,500.
To determine the bonus for a single highest sale in the range of $20,000–$39,999, use the given table.
The bonus for a single highest sale in the given range is $1,000.
Divide the given total bonus pay (9,500) by the bonus for each sale (1,000) to determine the maximum number of bonuses that could have been paid.
| Maximum number of bonuses | |
| Plug in values | |
| Divide |
The number of bonuses paid must be a whole number. The largest whole number less than 9.5 is 9, so the maximum number of bonuses that could be paid is 9.
Therefore, the maximum number of representatives is 9.
(Choices A and B) 4 and 5 may result from mistakenly dividing the highest value ($39,999) in the given range by the total bonus pay ($9,500).
(Choice D) 10 may result from mistakenly rounding 9.5 up to 10. However, the total bonus pay ($9,500) is not enough to pay a bonus of $1,000 to 10 representatives.
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